BOLTZMANN DISTRIBUTION

Case I: Prob of atom A having P(n):

P(3) = 1/20 = .05

P(2) = 3/20 = .15

P(1) = 6/20 = .30

P(0) =10/20 = .50

Note that the sum of probabilities equals 1 as it should:

?P(n) = 20/20 = 1.00

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