BOLTZMANN DISTRIBUTION

CASE II: four atoms having five units of energy:

Prob of atom A having:

P(5) = 1/56 = .018

P(4) = 3/56 = .054

P(3) = 6/56 = .107

P(2) =10/56 = .179

P(1) =15/56 = .268

P(0) =21/56 = .375

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