It usually appears that there are almost as many ways to solve problems as there are problems to be solved; but on closer examination it is possible to identify patterns and techniques for successful problem solving. It is important to be systematic, because such an approach will work even when "instinct" fails. An organized approach is also useful since it helps keep your thoughts in order.
Individual strengths and weaknesses need to be factored into your problem solving strategy. Take the ideas presented here and use them as the basis for your own approach.
Almost every engineering problem-solving technique boils down to five broad steps
Describing the problem requires you to understand what is given and what is needed. Often it is useful to develop a drawing or graph to help you at this stage.
It is critical to identify the facts of the problem. Some will be known, others will be missing. Sometimes the hardest part of a problem is locating missing information. Be sure that you stick to relevant facts. Don't waste time with facts that don't bear on your problem.
By identify the principles, the technique is telling you to look for the tools you have to solve the problem -- physical laws, relating equations, etc. Once you've decided what rules apply, you may need to go back and find more information.
Once you've done the first three steps, you've done the hard part. Now you just add numerical values and do the math. Don't forget to check your solution afterward. It is important that you be able to judge when an answer "makes sense".
The five steps can be expanded to provide a detailed solution guide tailored to the solution of balance problems. Notice that the approach has the same basic outline as that above.
A complete material balance problem, ready for solution, will consist of:
Dilute sulfuric acid has to be added to dry charged batteries at service stations in order to activate the battery. You are asked to prepare a new batch of acid as follows: A tank of old weak battery acid (H2SO4) solution contains 12.43 mass percent H2SO4 (the remainder is water). If 200 kg of 77.7% acid are added to the tank, and the final solution is 18.63% H2SO4, how many kilograms of battery acid have been made?
First, think in general terms about what is going on. Two streams are being mixed to create a third. Only mixing is taking place, so there are no reactions to worry about. The desired answer is the amount (in mass units) of product (the 19% solution) made.
Now, we're ready for a sketch, and we'll assign variable names to the streams. I'll let P (kg) be the amount of product, F (kg) the amount of old solution, N (kg) the amount of new solution.
On to choosing a basis -- which stream should I use?
Is the problem adequately specified? I can do this two ways: either by determining the degrees of freedom, or by just looking at the equations. The latter is easy for this problem:
If I go the degrees of freedom route, I need to count a little more carefully:
Do I need more information? I've got compositions on all three streams. I don't need to worry about densities or anything like that. It looks like no other data are needed.
I've already noted that I can write two independent balances. Which combination would make the most sense?
The answer I'm looking for, P shows up in all three equations. If it didn't, I'd probably want to make sure that I used an equation that included my answer directly.
Compositions are all given as mass fractions of acid. In order to do the water balance, I'd have to use (1-x) terms. This isn't hard, but it is slightly more work, so I'll stay away from the water balance for now.
I like to see "zeros" in problems, as a couple of zeros will usually lead to a sequential (instead of simultaneous) solution. Unfortunately, I don't have any in this problem.
OK, then, we'll use a total material balance and an acid balance.
Writing the total material balance:
Thus we need to solve two equations in two unknowns.
| 200 = P - F |
| 155.4 = 0.1863P - 0.1243F |
| P = 2105.5 kg |
| F = 1905.5 kg |
Sidebar: You won't always get answers that work nicely. Roundoff error is a significant culprit. Try not to round off numbers until you get a final answer.
We save some time on the next step because we chose the basis to eliminate scaling, and so we don't have to do it here.
Does the solution make sense? Well, P is greater than F -- if it weren't, we'd have a problem.
While we're here, let's see what would have happened with a different basis: What if I'd chosen N=100 kg?
My equations would have become:
| 100 = P - F |
| 77.7 = 0.1863P - 0.1243F |
| P = 1052.7 kg |
| F = 952.7 |
If we'd decided to go with a basis of P=100 kg, it would change several steps -- notably, we cannot use the value of N given in the problem statement. We've "specified" P, so if we keep the given value of N, the degrees of freedom will be:
With the basis, P=100, our equations become:
| 100 = N + F |
| 18.63 = 0.777*N + 0.1243F |
| N = 9.5 kg |
| F = 90.5 kg |
See how the answers vary just a bit -- that's roundoff and scaling for you!
A news item in ASEE Prism (October 1996, p. 10) listed the areas where students commonly have difficulties in problem solving. Paraphrased, these are:
References:
R.M. Price
Original: 6/13/94
Modified: 10/3/94, 6/26/96, 5/20/97; 1/4/2005
Copyright 1997, 2005 by R.M. Price -- All Rights Reserved